Question
the bob of a simple pendulum moves simple harmonically with amplitude 8.0cm and perid 2.00s. its mass is o.50kg. the motion of the bob is undemped. calculate the maximum values for:-
{a} the speed of the bob
{b} the kinetic energy of the bob.
{a} the speed of the bob
{b} the kinetic energy of the bob.
Answers
say
x = A sin (2 pi t/T) = 0.08 (sin pi t)
then
v = 0.08 pi cos (pi t)
so max v = 0.08 pi
and (1/2) m v^2 = (1/2)(0.50) pi^2 (0.0064)
x = A sin (2 pi t/T) = 0.08 (sin pi t)
then
v = 0.08 pi cos (pi t)
so max v = 0.08 pi
and (1/2) m v^2 = (1/2)(0.50) pi^2 (0.0064)
God punish you
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