Asked by Elisa
A simple pendulum is 9.00 m long.
(a) What is the period of simple harmonic motion for this pendulum if it is hanging in an elevator accelerating upward at 2.00 m/s2?
I keep getting 6.7, but it's wrong
(a) What is the period of simple harmonic motion for this pendulum if it is hanging in an elevator accelerating upward at 2.00 m/s2?
I keep getting 6.7, but it's wrong
Answers
Answered by
drwls
If it is accelerating upward at that rate, the effective value g is
g' = g + a = 11.8 m/s^2
instead of 9.8 m/s^2.
The period will be 2 pi sqrt(L/g')= 5.48 s
Apparently you used g' = g - a. That only applies if the elevator is accelerating downwards.
g' = g + a = 11.8 m/s^2
instead of 9.8 m/s^2.
The period will be 2 pi sqrt(L/g')= 5.48 s
Apparently you used g' = g - a. That only applies if the elevator is accelerating downwards.
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