Asked by hurd
a 10 kg weight is on an inclined plane. 10 ft long and 6 ft high. if there is no friction, what force parallel to the plane will prevent the body from slidin?
Answers
Answered by
drwls
The gravity force component parallel to the plane is
M*g*sinA, where
sinA = 0.6.
A is the angle that the incline makes with the horizontal. It is 36.87 degrees.
M*g*sinA = 58.8 N
applied up and along the incline will prevent the body from sliding.
M*g*sinA, where
sinA = 0.6.
A is the angle that the incline makes with the horizontal. It is 36.87 degrees.
M*g*sinA = 58.8 N
applied up and along the incline will prevent the body from sliding.
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