Question
Consider a block on an incline plane. The coefficients
of static and kinetic friction between
the block and the incline are µs = 0.353 and µk = 0.31.
Calculate the critical angle θc, where the block just begins to slide.
Answer in units of ◦.
The block weighs 1kg.
Please help. I don't know what to do.
of static and kinetic friction between
the block and the incline are µs = 0.353 and µk = 0.31.
Calculate the critical angle θc, where the block just begins to slide.
Answer in units of ◦.
The block weighs 1kg.
Please help. I don't know what to do.
Answers
Damon
all that matters is mu static
normal force = m g cos T
so Friction force = .353 m g cos T
force down slope = m g sin T
m g sin T = .353 m g cos T
tan T = .353
normal force = m g cos T
so Friction force = .353 m g cos T
force down slope = m g sin T
m g sin T = .353 m g cos T
tan T = .353
I dont like physics
so if i do tan^1(.353) that should be my answer?
Damon
yes
I dont like physics
my computer said it was wrong...
I have online hw and im stuck on this one. i tried that answer and it said it was incorrect
I have online hw and im stuck on this one. i tried that answer and it said it was incorrect
Damon
I get 19.4 degrees to three significant figures
I dont like physics
that is right. thx so much bro
Damon
You are welcome.
I dont like physics
If you can, ive got two other problems that i don't know how to do.
A block is at rest on the incline shown in
the figure. The coefficients of static and kinetic
friction are µs = 0.62 and µk = 0.53,
respectively.
The acceleration of gravity is 9.8 m/s
2
What is the largest angle which the incline
can have so that the mass does not slide down
the incline?
Answer in units of ◦
.
A block is at rest on the incline shown in
the figure. The coefficients of static and kinetic
friction are µs = 0.62 and µk = 0.53,
respectively.
The acceleration of gravity is 9.8 m/s
2
What is the largest angle which the incline
can have so that the mass does not slide down
the incline?
Answer in units of ◦
.
I dont like physics
just realized why it was wrong the first time. I was doing tan^-1(3.53