Asked by anonymous

A frictionless incline is 5.00 m long (the distance from the top of the incline to the bottom, measured along the incline). The vertical distance from the top of the incline to the bottom is 4.03 m. A small block is released from rest at the top of the incline and slides down the incline.
-how long does it take to reach the ground?
-what is the speed of the block before hitting the ground?

Answers

Answered by Damon
(1/2) m v^2 = m g h
v = sqrt (2 g h) = sqrt(2*9.81*4.03)

average speed = v/2
5.00 = (v/2) t
t = 10/v
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