Asked by Alex
A crate is placed on an inclined board as shown in the figure below. One end of the board is hinged so that the angle θ is adjustable. If the coefficient of static friction between the crate and the board is μS = 0.37, what is the value of θ at which the crate just begins to slip?
Answers
Answered by
Elena
The equation of motion (in vector form)
according to the 2nd Newton’s Law is
vector(m•g) +vector F(fr)+ vector N =0.
Projections on the x- and y-axes
x: m•g•sinα - F(fr) = 0,
y: - m•g•cosα + N = 0.
F(fr) = μ•N = μ •m•g•cosα,
m•g•sinα - μ •m•g•cosα =0,
tanα = μ,
α =arctan μ =20.3º
according to the 2nd Newton’s Law is
vector(m•g) +vector F(fr)+ vector N =0.
Projections on the x- and y-axes
x: m•g•sinα - F(fr) = 0,
y: - m•g•cosα + N = 0.
F(fr) = μ•N = μ •m•g•cosα,
m•g•sinα - μ •m•g•cosα =0,
tanα = μ,
α =arctan μ =20.3º
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