Question
An aluminum bar has the desired length when at 10 degrees Celsius. How much stress is required to keep it at this length if the temperature increases to 33 degrees Celsius?
Answers
Bethany
The change in L = (Initial L)x(Force)/E/Area.
The change in L also = (Alpha)x(Initial L)x(Change in Temperature)
So, (Alpha)x(Change in Temperature)x(E) = Force/Area
So, (25x10^-6)x(23)x(70x10^9) = 4.0x10^7 N/m^2
The change in L also = (Alpha)x(Initial L)x(Change in Temperature)
So, (Alpha)x(Change in Temperature)x(E) = Force/Area
So, (25x10^-6)x(23)x(70x10^9) = 4.0x10^7 N/m^2