At 28.4 g sample of aluminum is heated to 39.4 degrees Celsius and then is placed in a calorimeter containing 50.0g of water. Temp of water increases from 21.00 degrees Celsius to 23.00 degrees Celsius. What is the specific heat of aluminum?

Answer 1

the sum of heats gained is zero.
HeatgainedAl+heatgainedwater=0
28.4*cAl*(23-39.4)+50*cWater*(23-21)=0

solve for cAl