Asked by Dee
a 55g aluminum block initially at 27degrees C absorbs 725J of heat. What is the final temp.
I know I need to use the equation
q=m*Cs*Delta T but I cannot figure out how to rearrange the equation to isolate Tf to get the answer.
Thanks for any help.
I know I need to use the equation
q=m*Cs*Delta T but I cannot figure out how to rearrange the equation to isolate Tf to get the answer.
Thanks for any help.
Answers
Answered by
DrBob222
My experience is NOT to try rearranging it before you subtitute. I think it is far easier to substitute, then solve the equation.
q = mass x specific heat x (Tf-Ti)
725 = 55 x specific heat Al x (Tf - 27).
What Al? about 0.3 or so J/g?
725 = 55 x 0.3 x (Tf-27)
725 = 55*0.3*Tf - (55*0.3*27)
Multiply all that stuff inside the parentheses and solve the resulting equation for Tf.
q = mass x specific heat x (Tf-Ti)
725 = 55 x specific heat Al x (Tf - 27).
What Al? about 0.3 or so J/g?
725 = 55 x 0.3 x (Tf-27)
725 = 55*0.3*Tf - (55*0.3*27)
Multiply all that stuff inside the parentheses and solve the resulting equation for Tf.
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