Question
What is the cell potential for the reaction
Mg(s) + Fe^2+(aq) -----> Mg^2+(aq) + Fe (s)
at 63 degrees celsius when [Fe^2+]= 3.30 M and [Mg^2+]= 0.110 M
Mg(s) + Fe^2+(aq) -----> Mg^2+(aq) + Fe (s)
at 63 degrees celsius when [Fe^2+]= 3.30 M and [Mg^2+]= 0.110 M
Answers
DrBob222
Find the Eo for the cell as written. Then Ecell =
Eocell + (RT/nF)lnQ
Q = (Mg^2+)/(Fe(2+)
Substitute and solve for Ecell.
Eocell + (RT/nF)lnQ
Q = (Mg^2+)/(Fe(2+)
Substitute and solve for Ecell.