Question

Calculate the cell potential for a cell based on the reaction
Cu(s) + 2Ag+(aq) -> Cu2+(aq) + 2Ag(s)
when the concentrations are as follows:
[Ag+]= 0.53 M, [Cu2+] = 0.9 M.
(The temperature is 25◦C and E0 = 0.4624 V.)
Answer in V.

Answer 1

Calculate Ehalfcell for the REDUCTION half equation from
Ehalfcell = Eo-(0.05016/n)log [(red)/(ox)]

Then reverse the half cell that is oxidized, (reverse the sign, also), then add to the reduction half cell. That will be Ecell.
Post your work if you get stuck.

Answer 2

I got:
0.4624-(.05016/2) log(.80/.34)= 98.569

and i don't get the second part where you reverse it and add it...do i add it to 98.569??