Calculate the cell potential for a cell based on the reaction

Cu(s) + 2Ag+(aq) -> Cu2+(aq) + 2Ag(s)
when the concentrations are as follows:
[Ag+]= 0.53 M, [Cu2+] = 0.9 M.
(The temperature is 25◦C and E0 = 0.4624 V.)
Answer in V.

2 answers

Calculate Ehalfcell for the REDUCTION half equation from
Ehalfcell = Eo-(0.05016/n)log [(red)/(ox)]

Then reverse the half cell that is oxidized, (reverse the sign, also), then add to the reduction half cell. That will be Ecell.
Post your work if you get stuck.
I got:
0.4624-(.05016/2) log(.80/.34)= 98.569

and i don't get the second part where you reverse it and add it...do i add it to 98.569??