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Potential of a cell is 0.1776 volts

Pb|Pb2+(??M)||Pb2+(1.0M)|Pb

I know i have to use Nernst's equation .. i just have no clue how to attempt this :S

2 answers

This is a concentration cell since the electrodes are the same but the molarities are different (we assume they are anyway).
Ecell = Eo-(0.0592/n)log Q
I would plug in 0.1776 for Ecell. Eo is always zero in a concn cell, n = 2 for this cell and solve for Q.
Q = (x/1M) and solve for x.
you don't make sense
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