Asked by Z
Cell Potential at Equilibrium
For a single galvanic cell based on the (unbalanced) reaction:
Ag+(aq) + Zn(s) = Zn2+(aq) + Ag(s)
What is the cell potential when the cell reaches equilibrium?
For a single galvanic cell based on the (unbalanced) reaction:
Ag+(aq) + Zn(s) = Zn2+(aq) + Ag(s)
What is the cell potential when the cell reaches equilibrium?
Answers
Answered by
DrBob222
Ag^+ + e ==> Ag(s)...... Ered = 0.800
Zn ==> Zn^2+ + 2e ........Eox = 0.762....Note the sign change.
======Add Ered + Eox = Ecell========================
2Ag^+ + Zn(s) ==> 2Ag(s) + Zn^2+ E<sup>o</sup><sub>cell</sub> = ?
Note: You so NOT multiply the 0.800 by 2.
Zn ==> Zn^2+ + 2e ........Eox = 0.762....Note the sign change.
======Add Ered + Eox = Ecell========================
2Ag^+ + Zn(s) ==> 2Ag(s) + Zn^2+ E<sup>o</sup><sub>cell</sub> = ?
Note: You so NOT multiply the 0.800 by 2.
Answered by
Z
Yes I also tried that already I got 1.56 V but it is still wrong.
Answered by
DrBob222
You're right. That 1.562 is the cell potential at the beginning when the electrolytes are at 1 M if these are standard cells. . When it reaches equilibrium the cell has been exhausted and the cell potential is zero.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.