Question
Cell Potential at Equilibrium
For a single galvanic cell based on the (unbalanced) reaction:
Ag+(aq) + Zn(s) = Zn2+(aq) + Ag(s)
What is the cell potential when the cell reaches equilibrium?
For a single galvanic cell based on the (unbalanced) reaction:
Ag+(aq) + Zn(s) = Zn2+(aq) + Ag(s)
What is the cell potential when the cell reaches equilibrium?
Answers
DrBob222
Ag^+ + e ==> Ag(s)...... Ered = 0.800
Zn ==> Zn^2+ + 2e ........Eox = 0.762....Note the sign change.
======Add Ered + Eox = Ecell========================
2Ag^+ + Zn(s) ==> 2Ag(s) + Zn^2+ E<sup>o</sup><sub>cell</sub> = ?
Note: You so NOT multiply the 0.800 by 2.
Zn ==> Zn^2+ + 2e ........Eox = 0.762....Note the sign change.
======Add Ered + Eox = Ecell========================
2Ag^+ + Zn(s) ==> 2Ag(s) + Zn^2+ E<sup>o</sup><sub>cell</sub> = ?
Note: You so NOT multiply the 0.800 by 2.
Z
Yes I also tried that already I got 1.56 V but it is still wrong.
DrBob222
You're right. That 1.562 is the cell potential at the beginning when the electrolytes are at 1 M if these are standard cells. . When it reaches equilibrium the cell has been exhausted and the cell potential is zero.