Asked by Brandon

A pressurized can of whipped cream has an internal pressure of 1.080 atm at 25°C. If it is placed in a freezer at -8°C, what is the new value for its internal pressure (in atmospheres)?

I did this but got a negative number that wasn't correct
Answered by DrBob222
If you will show you work I will find ?the error. Did you use kelvin for T.
Answered by Brandon
(1.080)(-8)=(265)(P)
-8.64=265P
265p/ -8.64= -30.67
Answered by DrBob222
You didn't answer my question and you did NOT use kelvin. You must convert celsius to kelvin.
kelvin = 273 + C.
Answered by Brandon
i thought i did
Answered by Brandon
298/-8.64=-34.49

298=273+20
Answered by DrBob222
No you didn't. Actually, you converted the -8C to kelvin, then used 265(the correct value for T2 and -8 (the same number) for T1.
K = 273 + C
25C = 298K since 273+ 25 = 298.
-8C
273-8 = 265K.

(P1/T1) = (P2/T2)
(1.08/298) = (P2/265)
P2 =
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