Asked by Jon
Assume that no denomenator equals 0.
(7x^2+3x-9)-(-x^2+8x-3)
= 7x^2+3x-9+x^2-8x+3
= (7x^2+x^2)+(3x-8x)+(-9+3)
= 8x^2+-5x+-6
= 8x^2-5x-6(answer)
(7x^2+3x-9)-(-x^2+8x-3)
= 7x^2+3x-9+x^2-8x+3
= (7x^2+x^2)+(3x-8x)+(-9+3)
= 8x^2+-5x+-6
= 8x^2-5x-6(answer)
Answers
Answered by
Dan
What exactly is your question? I don't even see a denominator anywhere :)
What you have is right so far. If you want to finish that question you need to use the quadratic formula
x = (-b +/- square root(b^2 - 4ac)) / 2a
x = (5 +/- square root (25 + 192)) / 16
x = (5 +/- square root (217)) / 16
which yields x1 = 1.23 and x2 = -0.61
What you have is right so far. If you want to finish that question you need to use the quadratic formula
x = (-b +/- square root(b^2 - 4ac)) / 2a
x = (5 +/- square root (25 + 192)) / 16
x = (5 +/- square root (217)) / 16
which yields x1 = 1.23 and x2 = -0.61
Answered by
Jon
(7x^2+3x-9)-(-x^2+8x-3) is the question. the rest is my work
Answered by
Dan
Your solution is perfect, did you just want confirmation?
Answered by
Jon
yes
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.