Assume that no denominator equals 0.

sqrt 16x^2y^4

= sqrt (4x)y^2
= 4xy^2(answer)

1 answer

Your answer is correct. Another possible answer is -4xy^2
Similar Questions
    1. answers icon 1 answer
    1. answers icon 1 answer
  1. Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
    1. answers icon 1 answer
  2. When I solve the inquality 2x^2 - 6 < 0,I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
    1. answers icon 0 answers
more similar questions