Question
Assume that no denominator equals 0.
sqrt12 - sqrt18 + 3sqrt50 + sqrt75
= (sqrt2^2*3) - (sqrt2*3^2) + (3sqrt2*5^2) + (sqrt3*5^2)
= (sqrt2^2*sqrt3) - (sqrt3^2*sqrt2) + (3sqrt5^2*sqrt2) + (sqrt5^2*sqrt3)
= (2*sqrt3) - (3*sqrt2) + (3sqrt5*sqrt2) + (5*sqrt3)
= 7sqrt3 + sqrt2 + sqrt5(answer)
sqrt12 - sqrt18 + 3sqrt50 + sqrt75
= (sqrt2^2*3) - (sqrt2*3^2) + (3sqrt2*5^2) + (sqrt3*5^2)
= (sqrt2^2*sqrt3) - (sqrt3^2*sqrt2) + (3sqrt5^2*sqrt2) + (sqrt5^2*sqrt3)
= (2*sqrt3) - (3*sqrt2) + (3sqrt5*sqrt2) + (5*sqrt3)
= 7sqrt3 + sqrt2 + sqrt5(answer)
Answers
no, your roots 3's are ok, but....
sqrt12 - sqrt18 + 3sqrt50 + sqrt75
= √(4*3) - √(9*2) +3√(25*2) + √(25*3)
= 2√3 - 3√2 + 15√2 + 5√3
= 7√3 + 12√2
sqrt12 - sqrt18 + 3sqrt50 + sqrt75
= √(4*3) - √(9*2) +3√(25*2) + √(25*3)
= 2√3 - 3√2 + 15√2 + 5√3
= 7√3 + 12√2
Related Questions
Simplify
sqrt12 + sqrt18 - sqrt27 + sqrt 50
thnx a lot any help is greatly appriceted....
thes...
Given: f(x) = X^2-x
evaluate: f(sqrt2 + 3)
I have worked out this and am stuck:
(sqrt2+3)^2 -...
divide and simplify the radical
(3+ sqrt18)/4 sqrt12
I'm not sure how to conjugate the denomin...
The product of 5sqrt27 and BLANK would yield a rational number.
a. sqrt12
b.sqrt9
c.4 sqrt2
d.sq...