Asked by Chelle
differentiate:
g(t)=tˆ3cos(t)
g(t)=tˆ3cos(t)
Answers
Answered by
Steve
using the product rule,
g' = 3t^2 cost + t^3 (-sint)
= t^2 (3cost - t sint)
g' = 3t^2 cost + t^3 (-sint)
= t^2 (3cost - t sint)
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