Asked by Natasha
Algebraically solve the system of equations using any method you wish
3x-10y+z=5
-4x+9y-z=-6
-13y+z=2
3x-10y+z=5
-4x+9y-z=-6
-13y+z=2
Answers
Answered by
Reiny
I would use substitution to start:
from the 3rd: z = 13y + 2
into the 1st:
3x - 10y + 13y + 2 = 5
3x + 3y = 3
x+y=1
into the 2nd:
-4x + 9y - 13y - 2 = -6
-4x - 4y = -4
x + y = 1
Ahhh,
x+y = 1 and x+y = 1 don't have a real solution.
So the system has no unique solution.
check my arithmetic
from the 3rd: z = 13y + 2
into the 1st:
3x - 10y + 13y + 2 = 5
3x + 3y = 3
x+y=1
into the 2nd:
-4x + 9y - 13y - 2 = -6
-4x - 4y = -4
x + y = 1
Ahhh,
x+y = 1 and x+y = 1 don't have a real solution.
So the system has no unique solution.
check my arithmetic
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.