Asked by cary
solve the system algebraically and graphically 32x^2+9y^2=324 3y^2-x^2=3
Answers
Answered by
Steve
32x^2+9y^2=324
3y^2-x^2=3
Since 3y^2 = x^2+3, we have
32x^2 + 3(x^2+3) = 324
I think you can solve that fairly easily, right?
The intersections are at x=±3, y=±2.
See the graphs at
http://www.wolframalpha.com/input/?i=plot+32x^2%2B9y^2%3D324%2C+3y^2-x^2%3D3
3y^2-x^2=3
Since 3y^2 = x^2+3, we have
32x^2 + 3(x^2+3) = 324
I think you can solve that fairly easily, right?
The intersections are at x=±3, y=±2.
See the graphs at
http://www.wolframalpha.com/input/?i=plot+32x^2%2B9y^2%3D324%2C+3y^2-x^2%3D3
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