Question
A ball is dropped from rest off a 27 m building.What is the maximum speed that the ball will reach?
Answers
drwls
Vmax = sqrt(2*g*H)
H is the building height (27 m) and g is the acceleration of gravity (9.8 m/s^2.
H is the building height (27 m) and g is the acceleration of gravity (9.8 m/s^2.