Asked by Anonymous
A ball is dropped from rest from the 4th story of a building, 14 meters off of the ground.
How much time passes before the ball hits the ground?
What is the ball’s velocity (speed AND direction) the split-second before it hits the ground? This answer is not zero - it hasn’t hit the ground yet!
Would I use the equation Vf=Vo+at
How much time passes before the ball hits the ground?
What is the ball’s velocity (speed AND direction) the split-second before it hits the ground? This answer is not zero - it hasn’t hit the ground yet!
Would I use the equation Vf=Vo+at
Answers
Answered by
Damon
well, eventually maybe
h = Hi + Vi t + .5 a t^2 and a = -9.81
0 = 14 + 0 - 4.9 t^2
t^2 = 14/4.9
t = 1.69 seconds
v = Vi + a t
v = 0 -9.81(1.69)
v = - 16.6 m/s
h = Hi + Vi t + .5 a t^2 and a = -9.81
0 = 14 + 0 - 4.9 t^2
t^2 = 14/4.9
t = 1.69 seconds
v = Vi + a t
v = 0 -9.81(1.69)
v = - 16.6 m/s
Answered by
Anonymous
The thing is, the only formulas my teacher gave me are these
Vf=Vo+at
Xf=Xo+Vot + 1/2at^2
Vf^2=Vo^2+2a(Xf-Xo)
So I dont want to use formulas I havent been taught but thank you!! But can you solve this problem with any of the above formulas
Vf=Vo+at
Xf=Xo+Vot + 1/2at^2
Vf^2=Vo^2+2a(Xf-Xo)
So I dont want to use formulas I havent been taught but thank you!! But can you solve this problem with any of the above formulas
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