Asked by EMMA
a ball is dropped from rest at 25m above the ground. how fast is it moving at 10 m above the ground and b) how much time does it take to reach the ground? no air resistance.
Answers
Answered by
Damon
at ten meters it has dropped 15 meters
(1/2) m v^2 = m g h
v^2 = 2 * 9.81 * 15 = 294.3
v = 17.2 m/s at 10 m above ground
d = (1/2) g t^2
25 = 4.9 t^2
t = 2.26 seconds
(1/2) m v^2 = m g h
v^2 = 2 * 9.81 * 15 = 294.3
v = 17.2 m/s at 10 m above ground
d = (1/2) g t^2
25 = 4.9 t^2
t = 2.26 seconds
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