Asked by sha

a ball dropped from rest at a height of 50 m above the ground. (a) what is the speed just before it hits the ground? (b) how long does it take to reach the ground?
Answered by Henry
a. V^2 = Vo^2 + 2g*h
Vo = 0
g = 9.8 m/s^2
h = 50 m.
Solve for V.
Answered by Anonymous
50
Answered by ridaa salman
(0)^2_2*9.8*50
Answered by Anonymous
a. -31
b . 3.16 sec
Answered by helen
490
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