Question
A stuntman sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 15.0 m/s, and the man is initially 2.45 m above the level of the saddle.
Answers
Damon
how long to fall 2.45 m
(1/2) 9.81 * t^2 = 2.45
t = .707 s
how far did the horse go?
15 * .707 = 10.6
Jump when the horse is 10.6 m away.
(1/2) 9.81 * t^2 = 2.45
t = .707 s
how far did the horse go?
15 * .707 = 10.6
Jump when the horse is 10.6 m away.