Question

A stuntman sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0 m/s, and the man is initially 2.75 m above the level of the saddle.

Please Show work!! I am completely lost!

Answer 1

find time it takes to fall 2.75m:

2.75 = 4.9t^2
t = .75s

distance covered by horse in .75s:

d = 10*.75 = 7.5m

man needs to drop down when the horse is 7.5m away. But watch out for the horse's head!

Answer 2

S1=V(0)T+a(g)t^2/2; T=0.75
S2=V(h)T; S2=7.5m