Asked by Petros

A stuntman drives a car over the top of a hill, the cross section of which can be approximated
by a circular arc of radius 250 m. What is the greatest speed at which he can drive without
the car leaving the road at the top of the hill?
Answered by bobpursley
At the top, weight = centripetal force

mg=mv^2/r

solve for v
Answered by Savannah
The normal force and the centripetal *force need to equal eachother if the car is to remain grounded, so N=mV^2/r or mg=mV^2/r and then the masses cancel and we have g=V^2/r or v^2=gr.
Answered by Anonymous
49.5 m/s
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