Question
A stunt woman sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The speed of the horse is 13.5 m/s, and the woman is initially 2.60 m above the level of the saddle.
(a) What must be the horizontal distance between the saddle and limb when the woman makes her move?
m
(b) How long is she in the air?
s
(a) What must be the horizontal distance between the saddle and limb when the woman makes her move?
m
(b) How long is she in the air?
s
Answers
Henry
a. h = Vo*t + 0.5g*t^2.= 2.60 m.
0 + 4.9t^2 = 2.60,
t^2 = 0.531,
Tf = 0.728 s = Fall time.
d = V*t = 13.5m/s * 0.728 s. = 9.83 m.
b. Tf = 0.728 s = Fall tm3e.
0 + 4.9t^2 = 2.60,
t^2 = 0.531,
Tf = 0.728 s = Fall time.
d = V*t = 13.5m/s * 0.728 s. = 9.83 m.
b. Tf = 0.728 s = Fall tm3e.