An object with mass 3.7 is attached to a spring with spring stiffness constant 270 and is executing simple harmonic motion. When the object is 2.5×10−2 from its equilibrium position, it is moving with a speed of 0.45 . what is the amplitude of the motion?

Answer 1

ω=sqrt(k/m)

v= ω•sqrt(A²-x²)