Asked by Lori

An object with mass 3.7 is attached to a spring with spring stiffness constant 270 and is executing simple harmonic motion. When the object is 2.5×10−2 from its equilibrium position, it is moving with a speed of 0.45 . what is the amplitude of the motion?
Answered by Elena
ω=sqrt(k/m)

v= ω•sqrt(A²-x²)
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