A stone with mass 0.8kg is attached to one end of a string 0.9m long . The string will break if its tension exceeds 600N. The stone is whirled in a horizontal circle ,the other end of the string remains fixed. Find the maximum speed , the stone can attain without breaking the string.

asked by Swagat khanal

8 years ago

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2 answers

m v^2/R = 600

0.8 v^2/0.9 = 600

answered by Damon

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answered by Mandeeo

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Question

A stone with mass 0.8kg is attached to one end of a string 0.9m long . The string will break if its tension exceeds 600N. The stone is whirled in a horizontal circle ,the other end of the string remains fixed. Find the maximum speed , the stone can attain without breaking the string.

2 answers

m v^2/R = 600

0.8 v^2/0.9 = 600

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Damon · Answer

m v^2/R = 600 0.8 v^2/0.9 = 600

Mandeeo · Answer

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