Asked by kerry
Find an equation for the line with the given properties:
1) Containing the points (1, 3) and (-1, 2)
2) Slope = -2/3; containing the point (1, -1)
3) X-intercept = 2; y-intercept = -1
4) Parallel to the line 2x – y = -2; containing the point (-1, 2)
5) Perpendicular to the line y= 1/2 x + 4 containing the point (1, -2)
1) Containing the points (1, 3) and (-1, 2)
2) Slope = -2/3; containing the point (1, -1)
3) X-intercept = 2; y-intercept = -1
4) Parallel to the line 2x – y = -2; containing the point (-1, 2)
5) Perpendicular to the line y= 1/2 x + 4 containing the point (1, -2)
Answers
Answered by
Steve
can you make no headway on any of them?
they are all just variations on
the line with slope m through (a,b) is
y-b = m(x-a)
they are all just variations on
the line with slope m through (a,b) is
y-b = m(x-a)
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