Asked by Anonymous
How would you expand and simplify the following equation?
"(3a + 4b) product dot (5a + 6b)"
Textbook answer: 15| a |^2 + 38a product dot b + 24| b |^2
"(3a + 4b) product dot (5a + 6b)"
Textbook answer: 15| a |^2 + 38a product dot b + 24| b |^2
Answers
Answered by
Damon
a is evidently a vector and so is b
in that case I would write a and b as
a = Ax i + Ay j
and
b = Bx i + By j
Then 3 a + 4 b = (3Ax+4Bx)i+(3Ay+4By)j
and 5 a + 6 b = (5Ax+6Bx)i+(5Ay+6By)j
Then the dot product of those two vectors is
(3Ax+4Bx)(5Ax+6Bx)+(3Ay+4By)(5Ay+6By)
which is
(15Ax^2+38AxBx+24Bx^2)+(15Ay^2+38AyBy+24By^2)
which is
15(Ax^2+Ay^2)+38(AxBx+AyBy)+24(Bx^2+By^2)
which is exactly what they said it should be :)
in that case I would write a and b as
a = Ax i + Ay j
and
b = Bx i + By j
Then 3 a + 4 b = (3Ax+4Bx)i+(3Ay+4By)j
and 5 a + 6 b = (5Ax+6Bx)i+(5Ay+6By)j
Then the dot product of those two vectors is
(3Ax+4Bx)(5Ax+6Bx)+(3Ay+4By)(5Ay+6By)
which is
(15Ax^2+38AxBx+24Bx^2)+(15Ay^2+38AyBy+24By^2)
which is
15(Ax^2+Ay^2)+38(AxBx+AyBy)+24(Bx^2+By^2)
which is exactly what they said it should be :)
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