Asked by Sierra
Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0
Answers
Answered by
Reiny
cos^2t+2cos(t)+1=0
(cost + 1)^2 = 0
cost + 1 = 0
cost = -1
t = 270°
(cost + 1)^2 = 0
cost + 1 = 0
cost = -1
t = 270°
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