Asked by fblazer90
Solve the equation in the interval [0, 2pi].
2sin(t)cos(t)-cos(t)+2sin(t)-1=0
Answer needs to be formatted as x={Insert answers here}pi
If the answer is something like pi/6 it simply goes in as 1/6th since pi is already given at the end.
2sin(t)cos(t)-cos(t)+2sin(t)-1=0
Answer needs to be formatted as x={Insert answers here}pi
If the answer is something like pi/6 it simply goes in as 1/6th since pi is already given at the end.
Answers
Answered by
Reiny
2sin(t)cos(t)-cos(t)+2sin(t)-1=0
cost(2sint - 1) + (2sint - 1) = 0
(2sint - 1)(cost + 1) = 0
sint = 1/2 or cost = -1
if sint = 1/2
t = π/6 or t = 5π/6
if cost = -1, look at your cosine curve,
t = π
cost(2sint - 1) + (2sint - 1) = 0
(2sint - 1)(cost + 1) = 0
sint = 1/2 or cost = -1
if sint = 1/2
t = π/6 or t = 5π/6
if cost = -1, look at your cosine curve,
t = π
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