Asked by Yana
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2cos^(2)\theta +\sqrt(2cos\theta )=2cos\theta +\sqrt(2)
Answers
Answered by
oobleck
why do you write "the interval 0 less than or equals theta less than 2 pi" and then go right ahead and say "0≤θ<2π" ? Just like to repeat yourself?
2cos^2θ + √(2cosθ) = 2cosθ + √2
Just by inspection, θ=0
and θ cannot be in QII or QIII, since there cosθ < 0
and since the function is even, solutions in QIV mirror those in QI.
2cos^2θ + √(2cosθ) = 2cosθ + √2
Just by inspection, θ=0
and θ cannot be in QII or QIII, since there cosθ < 0
and since the function is even, solutions in QIV mirror those in QI.
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