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Asked by Anonymous

solve the equation on the interval [0,2pi)

sin^2x=1
15 years ago

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Answered by Reiny
then
sinx = ± 1

looking at a standard sine curve we can see that
x = π/2 or x = 3π/2
15 years ago
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solve the equation on the interval [0,2pi)

sin^2x=1

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