Asked by Anonymous
solve the equation on the interval [0,2pi)
sin^2x=1
sin^2x=1
Answers
Answered by
Reiny
then
sinx = ± 1
looking at a standard sine curve we can see that
x = π/2 or x = 3π/2
sinx = ± 1
looking at a standard sine curve we can see that
x = π/2 or x = 3π/2
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