Asked by Lauren
What is the minimum work in joules needed to push a 1460 kg car 14.0 m up a 12.5 degree incline? (Ignore friction.)
Answers
Answered by
ajayb
Work required = Gain in PE
= m*g*h
= 1460*9.8*14Sin12.5 J
(h-vertical height gained)
= m*g*h
= 1460*9.8*14Sin12.5 J
(h-vertical height gained)
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