Question
What is the minimum work needed to push a 975 kg car 230 m up along a 17.5° incline?
Assume the effective coefficient of friction retarding the car is 0.20?
Assume the effective coefficient of friction retarding the car is 0.20?
Answers
bobpursley
work needed= change of PE+work done on friction
= m*g*230*sin17.5 + mg*mu*cos17.5*230
check that and think it out.
= m*g*230*sin17.5 + mg*mu*cos17.5*230
check that and think it out.