What is the minimum work needed to push a 800 kg car 860 m up along a 9.0 degree incline? Ignore friction. Then assume the effective coefficient of friction retarding the car is 0.22. I have no idea where to start this problem

Answer 1

no friction? work= mgh= mg*860sin9

friction? friction= mg*mu*cos9* 860
min work= mgh+mg*mu*cos9*860

You start the problem by applying basic, fundamental relationships.

Answer 2

I am not understanding how to do the second part...assume the effective coefficient of friction retarding the car is 0.22. I got the first part and the answer is 1.1*10^6, how do I figure out the second part?

Answer 3

see the last two lines of my response. Solve for min work.