Asked by Luricela

(a) What is the minimum work needed to push a 1150 kg car 240 m up a 17.5° incline with zero friction?
(b) What is the minimum work needed if the effective coefficient of friction is 0.20?
Answered by drwls
(a) Mass * g * (elevation gain)
(b) Answer (a) + friction work.

(friction work = 240 m * M g cos17.5)
Answered by tbuir
B) answer (a) + (240m*.20*1150kg*9.8*cos17.5)

he forgot the effective coefficient of .20 ...
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