Question
(a) What is the minimum work needed to push a 1150 kg car 240 m up a 17.5° incline with zero friction?
(b) What is the minimum work needed if the effective coefficient of friction is 0.20?
(b) What is the minimum work needed if the effective coefficient of friction is 0.20?
Answers
drwls
(a) Mass * g * (elevation gain)
(b) Answer (a) + friction work.
(friction work = 240 m * M g cos17.5)
(b) Answer (a) + friction work.
(friction work = 240 m * M g cos17.5)
tbuir
B) answer (a) + (240m*.20*1150kg*9.8*cos17.5)
he forgot the effective coefficient of .20 ...
he forgot the effective coefficient of .20 ...