Asked by Jen
                Find the magnitude of the gravitational attraction force that the earth exerts on a 62-kilogram astronaut who is 8.00 X 10^7 meters away from the center of the earth. 
Useful numbers: M^earth=5.98 X 10^24kg; G=6.67 X 10^-11 N*m^2kg^-2
Please walk me through your steps, don't just suggest a formula-thank you.
            
        Useful numbers: M^earth=5.98 X 10^24kg; G=6.67 X 10^-11 N*m^2kg^-2
Please walk me through your steps, don't just suggest a formula-thank you.
Answers
                    Answered by
            Elena
            
    This is only one step - The Universal Law of Gravitation
F=G• m•M/(R)²
R= 8.00 X 10^7 m,
m=62 kg
    
F=G• m•M/(R)²
R= 8.00 X 10^7 m,
m=62 kg
                    Answered by
            Jen
            
    Question though, the answer in the book says that the answer is 3.9 Newtons...do I need to convert this answer or something?
    
                    Answered by
            Elena
            
    F=G• m•M/(R)² =
=6.67•10^-11•62•5.98•10^24/(8• 10^7)²=3.87 N ≈3.9 N
    
=6.67•10^-11•62•5.98•10^24/(8• 10^7)²=3.87 N ≈3.9 N
                    Answered by
            Jen
            
    Fabulous! Thank you!!!
    
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