Asked by linda
Find the magnitude of (2-i)(1+3i)(3+4i)
Answers
Answered by
Reiny
First of all let's expand this
(2-i)(1+3i)(3+4i)
= (2-i)(3 + 13i + 12i^2)
= (2-i)(13i - 9) , remember that i^2 = -1
= 26i - 18 - 13i^2 + 9i
= -5 + 35i
magnitude
= √(25 + 1225)
= √1250
= 25√2
(2-i)(1+3i)(3+4i)
= (2-i)(3 + 13i + 12i^2)
= (2-i)(13i - 9) , remember that i^2 = -1
= 26i - 18 - 13i^2 + 9i
= -5 + 35i
magnitude
= √(25 + 1225)
= √1250
= 25√2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.