Question

How do I find the magnitude from this data:
theta_1 = 44.9 theta_2 = 146.1
A = 4.8 cm B = 8.7 cm

Answer 1

of vector (A + B)

Answer 2

I don't know where theta 1 and theta 2 are, but have you considered drawing the figure, then using the law of sines?

Answer 3

theta one goes with A and theta two goes with B. I know I'm supposed to use |A+B| =sqrt[ (A+B)x^2 + (A+B)y^2 ], but I am having troubles on which numbers I have to plug in for each value.

Answer 4

assuming the θ values are with respect to the positive x-axis, then

A = 4.8 cos44.9 i + 4.8 sin 44.9 j = 3.40i + 3.39j
B = -7.22i + 4.85j

now just add 'em up and take ||

Answer 5

I keep getting the wrong answer. I got 4.42, is that wrong?

Answer 6

(A+B)x = -3.82
(A+B)y = 8.24

14.6 + 67.9 = 82.5
so
9.08