Asked by Evans Bolt

find the acceleration due gravity on the
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )

Answers

Answered by bobpursley
gravity field: 9.8N/kg * (16.7/3.89^2)=10.8 m/s^2 check that
Answered by Steve
g on earth is 9.8 m/s^2

That means that g = GM/r^2 = 9.8
Now plug in your new values and you have

G(16.7M)/(3.89r^2) = (16.7/3.89^2)GM/r^2 = 1.1036g = ?
Answered by Evans Bolt
find the acceleration due gravity on the
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
(Answer 7.34Me)
Answered by bobpursley
Your answer is wrong.
Answered by Evans Bolt
alright. Thanks because I have been trying and not getting it. And please make yours more clearer and understandable for me . thanks
Answered by bobpursley
gravity is directly proportional to mass and the reciprocal of radius squared. If you dont understand, see law of gravity.
Answered by Damon
9.8 * Re^2/Rn^2 * Mn/Me

= 9.8 *1/3.89^2 * 16.7

= 10.8

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