Asked by Evans Bolt
                find the acceleration due gravity on the
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
            
        surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
Answers
                    Answered by
            bobpursley
            
    gravity field: 9.8N/kg * (16.7/3.89^2)=10.8 m/s^2  check that
    
                    Answered by
            Steve
            
    g on earth is 9.8 m/s^2
That means that g = GM/r^2 = 9.8
Now plug in your new values and you have
G(16.7M)/(3.89r^2) = (16.7/3.89^2)GM/r^2 = 1.1036g = ?
    
That means that g = GM/r^2 = 9.8
Now plug in your new values and you have
G(16.7M)/(3.89r^2) = (16.7/3.89^2)GM/r^2 = 1.1036g = ?
                    Answered by
            Evans Bolt 
            
    find the acceleration due gravity on the
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
(Answer 7.34Me)
    
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
(Answer 7.34Me)
                    Answered by
            bobpursley
            
    Your answer is wrong.
    
                    Answered by
            Evans Bolt 
            
    alright. Thanks because I have been trying and not getting it.  And please make yours more clearer and understandable for me . thanks 
    
                    Answered by
            bobpursley
            
    gravity is directly proportional to mass and the reciprocal of radius squared.  If you dont understand, see law of gravity. 
    
                    Answered by
            Damon
            
    9.8 * Re^2/Rn^2  * Mn/Me
= 9.8 *1/3.89^2 * 16.7
= 10.8
    
= 9.8 *1/3.89^2 * 16.7
= 10.8
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