find the acceleration due gravity on the
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
7 answers
gravity field: 9.8N/kg * (16.7/3.89^2)=10.8 m/s^2 check that
g on earth is 9.8 m/s^2
That means that g = GM/r^2 = 9.8
Now plug in your new values and you have
G(16.7M)/(3.89r^2) = (16.7/3.89^2)GM/r^2 = 1.1036g = ?
That means that g = GM/r^2 = 9.8
Now plug in your new values and you have
G(16.7M)/(3.89r^2) = (16.7/3.89^2)GM/r^2 = 1.1036g = ?
find the acceleration due gravity on the
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
(Answer 7.34Me)
surface of Neptune. given that mass of Neptune is 16.7
times that of the earth and the radius of Neptune is 3.89
times that of the earth (Re = 6380 km )
(Answer 7.34Me)
Your answer is wrong.
alright. Thanks because I have been trying and not getting it. And please make yours more clearer and understandable for me . thanks
gravity is directly proportional to mass and the reciprocal of radius squared. If you dont understand, see law of gravity.
9.8 * Re^2/Rn^2 * Mn/Me
= 9.8 *1/3.89^2 * 16.7
= 10.8
= 9.8 *1/3.89^2 * 16.7
= 10.8
1 answer