Asked by John
Find the acceleration of the block of mass M = 4.79 kg (m = 4.03) (KE = 0.1)
Answers
Answered by
Henry
KE = 0.5m*V^2 = 0.1 J.
2.395*V^2 = 0.1.
V^2 = 0.04175.
Vo = 0.204 m/s.
a = (Vf^2-Vo^2)/2d.
a=(0-(0.204)^2) / 8.06=-5.16^10^-3 m/s^2
2.395*V^2 = 0.1.
V^2 = 0.04175.
Vo = 0.204 m/s.
a = (Vf^2-Vo^2)/2d.
a=(0-(0.204)^2) / 8.06=-5.16^10^-3 m/s^2
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