Question
Find the acceleration of a box being pulled with an applied force of 320.0N at an angle of 30° from the horizontal. The µk between the floor and the box is 0.30
the box weighs 80 kg
the box weighs 80 kg
Answers
henry2,
Mg = 80*9.8 = 784 N. = Wt. of box = Normal force, Fn.
F = 320*cos30 = 277 N. = hor. component of applied force.
u*Fn = 0.3*784 = 235 N. = Force of kinetic friction.
F-u*Fn = M*a
277-235 = 80a
a = ____ m/s^2.
F = 320*cos30 = 277 N. = hor. component of applied force.
u*Fn = 0.3*784 = 235 N. = Force of kinetic friction.
F-u*Fn = M*a
277-235 = 80a
a = ____ m/s^2.