Asked by DK
Derivative of y=in((e^-2x)(cos4x))
Answers
Answered by
Steve
y = ln((e^(-2x))(cos4x))
= ln(e^-2x) + ln(cos 4x)
= -2x + ln(cos 4x)
y' = -2 - 4sin4x/cos4x
= -2 - 4tan4x
= ln(e^-2x) + ln(cos 4x)
= -2x + ln(cos 4x)
y' = -2 - 4sin4x/cos4x
= -2 - 4tan4x
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