Asked by dawn
What's the derivative of
f(x)=(x^2-1)(3x^3-6x+5)-4(4x^2+2x+1)
f(x)=(x^2-1)(3x^3-6x+5)-4(4x^2+2x+1)
Answers
Answered by
Reiny
f'(x) = (x^2-1)(9x^2 - 6) + (3x^3-6x+5)(2x) - 4(8x+2)
expand and simplify
expand and simplify
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