Question
A boat moving at 40 km/h is crossing a river in which the current is flowing at 10 km/h. In what direction should the boat head if it is to reach a point on the other side of the river directly opposite its starting point?
Answers
bobpursley
the upstream component is vboat*sinTheta
sinTheta=vstream/vboat=.25
theta=....
sinTheta=vstream/vboat=.25
theta=....
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