Asked by Neil
a speed boat is moving though the water at a speed of 28 m/s when the engine stalls. the boat comes to a halt over 120m, what is the time it takes to stop and what is the acceleration.
im trying to figure it out but i don't know what kinematic equation to use
im trying to figure it out but i don't know what kinematic equation to use
Answers
Answered by
ipnb
v^2 = v0^2 + 2ad so 0 = 28(m/s)^2 + 2(a)(120m)
solve for a
120m = ((0(m/s) + 28(m/s))/2) * t
solve for t
solve for a
120m = ((0(m/s) + 28(m/s))/2) * t
solve for t
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